/* * CDDL HEADER START * * The contents of this file are subject to the terms of the * Common Development and Distribution License (the "License"). * You may not use this file except in compliance with the License. * * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE * or http://www.opensolaris.org/os/licensing. * See the License for the specific language governing permissions * and limitations under the License. * * When distributing Covered Code, include this CDDL HEADER in each * file and include the License file at usr/src/OPENSOLARIS.LICENSE. * If applicable, add the following below this CDDL HEADER, with the * fields enclosed by brackets "[]" replaced with your own identifying * information: Portions Copyright [yyyy] [name of copyright owner] * * CDDL HEADER END */ /* * Copyright 2008 Sun Microsystems, Inc. All rights reserved. * Use is subject to license terms. */ .file "strlen.s" /* * strlen(s) * * Given string s, return length (not including the terminating null). * * Fast assembler language version of the following C-program strlen * which represents the `standard' for the C-library. * * size_t * strlen(s) * register const char *s; * { * register const char *s0 = s + 1; * * while (*s++ != '\0') * ; * return (s - s0); * } */ #include <sys/asm_linkage.h> ! The object of strlen is to, as quickly as possible, find the ! null byte. To this end, we attempt to get our string aligned ! and then blast across it using Alan Mycroft's algorithm for ! finding null bytes. If we are not aligned, the string is ! checked a byte at a time until it is. Once this occurs, ! we can proceed word-wise across it. Once a word with a ! zero byte has been found, we then check the word a byte ! at a time until we've located the zero byte, and return ! the proper length. .align 32 ENTRY(strlen) andcc %o0, 3, %o4 ! is src word aligned bz,pt %icc, .nowalgnd mov %o0, %o2 cmp %o4, 2 ! is src half-word aligned be,a,pn %icc, .s2algn lduh [%o2], %o1 ldub [%o2], %o1 tst %o1 ! byte zero? bz,pn %icc, .done cmp %o4, 3 ! src is byte aligned be,pn %icc, .nowalgnd inc 1, %o2 lduh [%o2], %o1 .s2algn: srl %o1, 8, %o4 tst %o4 bz,pn %icc, .done andcc %o1, 0xff, %g0 bz,pn %icc, .done inc 1, %o2 inc 1, %o2 .nowalgnd: ld [%o2], %o1 sethi %hi(0x01010101), %o4 sethi %hi(0x80808080), %o5 or %o4, %lo(0x01010101), %o4 or %o5, %lo(0x80808080), %o5 andn %o5, %o1, %o3 sub %o1, %o4, %g1 andcc %o3, %g1, %g0 bnz,a,pn %icc, .nullfound sethi %hi(0xff000000), %o4 ld [%o2+4], %o1 inc 4, %o2 .loop: ! this should be aligned to 32 inc 4, %o2 andn %o5, %o1, %o3 ! %o5 = ~word & 0x80808080 sub %o1, %o4, %g1 ! %g1 = word - 0x01010101 andcc %o3, %g1, %g0 bz,a,pt %icc, .loop ld [%o2], %o1 dec 4, %o2 sethi %hi(0xff000000), %o4 .nullfound: andcc %o1, %o4, %g0 bz,pn %icc, .done ! first byte zero srl %o4, 8, %o4 andcc %o1, %o4, %g0 bz,pn %icc, .done ! second byte zero inc 1, %o2 srl %o4, 8, %o4 andcc %o1, %o4, %g0 bz,pn %icc, .done ! thrid byte zero inc 1, %o2 inc 1, %o2 ! fourth byte zero .done: retl sub %o2, %o0, %o0 SET_SIZE(strlen)