[TUHS] C declarations.
    Ron Natalie 
    ron at ronnatalie.com
       
    Mon May 15 10:23:31 AEST 2017
    
    
  
It's a pointer.
 
Ø   Of course it is! But that doesn't mean that it SHOULD be, which is the point.
 
Actually, it is **Not a pointer**, it gets passed as a pointer, but it is an array on both ends.
 
 
The implicit conversion of the array name to a pointer to its first item is a different issue.   This bothers me less, but it’s still hokie in my opinion.
 
 
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