[TUHS] C declarations.
Ron Natalie
ron at ronnatalie.com
Mon May 15 10:23:31 AEST 2017
It's a pointer.
Ø Of course it is! But that doesn't mean that it SHOULD be, which is the point.
Actually, it is **Not a pointer**, it gets passed as a pointer, but it is an array on both ends.
The implicit conversion of the array name to a pointer to its first item is a different issue. This bothers me less, but it’s still hokie in my opinion.
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