2 Oct
2006
2 Oct
'06
6:44 a.m.
hi all,
I just started to read the source code of V6 with Lion's book.
But before I went far I was stopped by m40.s
0636: mov $USIZE-1/<8|6, (r1)+
What does the slash "/" stand for?
I guess this line should be
mov $USIZE-1<<8|6, (r1)+
Is "/<" the same as "<<"?
I checked in Unix PDP11 Assemble Refrence Manual but didn't find a clue.
Is it the right place to ask such question?
Thanks in advance
Regards,
Qinglai
2 Oct
2 Oct
12:50 p.m.
On Mon, Oct 02, 2006 at 09:44:58AM +0300, jigsaw wrote:
But before I went far I was stopped by m40.s
0636: mov $USIZE-1/<8|6, (r1)+
In my printed copy it is a \<, not a /<
What does the slash "/" stand for?
/ would start a comment
I guess this line should be
mov $USIZE-1<<8|6, (r1)+
I don't know for sure, but I doubt that the assembler will understand
this C syntax.
This piece of code is commented on page 6-2:
'The value 007406 is obtained by shifting the octal value 017 eight
places to the left and then "or"ing in the value of 6;'
--
%SYSTEM-F-ANARCHISM, The operating system has been overthrown
12:59 p.m.
hi Hans,
It's my mistake - it is \ rather than /
And refer to the assambler manual for UNIX v7, the "/<" stands for
"shift left", i.e., <<.
Regards,
Qinglai
On 10/2/06, Hans Rosenfeld <rosenfeld(a)grumpf.hope-2000.org> wrote:
On Mon, Oct 02, 2006 at 09:44:58AM +0300, jigsaw
wrote:
But before I went far I was stopped by m40.s
0636: mov $USIZE-1/<8|6, (r1)+
In my printed copy it is a \<, not a /<
What does the slash "/" stand for?
/ would start a comment
I guess this line should be
mov $USIZE-1<<8|6, (r1)+
I don't know for sure, but I doubt that the assembler will understand
this C syntax.
This piece of code is commented on page 6-2:
'The value 007406 is obtained by shifting the octal value 017 eight
places to the left and then "or"ing in the value of 6;'
--
%SYSTEM-F-ANARCHISM, The operating system has been overthrown
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jigsaw